2(x-4)^2-7=1

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Solution for 2(x-4)^2-7=1 equation: 



2(x-4)^2-7=1

We move all terms to the left:

2(x-4)^2-7-(1)=0

We add all the numbers together, and all the variables

2(x-4)^2-8=0

We move all terms containing x to the left, all other terms to the right

2(x-4)^2=8

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